A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is
Text Solution
Verified by ExpertsThe correct answer is:
B
Measured diameter of ball = Main scale reading + Circular scale reading × least count
= 5 mm + (25) × (0.01 mm) = 5.25 mm
Actual diameter = measured diameter – zero error
= (5.25 mm) – (– 0.04 mm)
= 5.29 mm
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